(x+3)(x-5)=x^2+1

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Solution for (x+3)(x-5)=x^2+1 equation: 



(x+3)(x-5)=x^2+1

We move all terms to the left:

(x+3)(x-5)-(x^2+1)=0

We get rid of parentheses

-x^2+(x+3)(x-5)-1=0

We multiply parentheses ..

-x^2+(+x^2-5x+3x-15)-1=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-5x+3x-15)-1=0

We get rid of parentheses

-1x^2+x^2-5x+3x-15-1=0

We add all the numbers together, and all the variables

-2x-16=0

We move all terms containing x to the left, all other terms to the right

-2x=16

x=16/-2

x=-8

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